Overpass API developpement

[mmd <>]

rel['key1'='value1']['key2'='value2'] will do, if I got your issue right.

On Thu, Dec 17, 2015 at 12:50 PM, Malcolm Herring <> wrote:

I need to perform an intersection, but there appears to be no native operator for this. So I am attempting to do this with unions & differences.

What I require: rel['key1'='value1'] AND rel['key2'='value2']

If I write: (rel['key1'='value1'] - rel['key2'!='value2'])

Will this work even if a relation in the input set has no tag with 'key2'? I cannot find a definition of the "!=" operator.